<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
The correct answer that would best fit the given statement above would be the third option. <span>In a genome-wide expression study using a DNA microarray assay, each well is used to detect the expression of a specific gene by a cell. Hope this answers your question. Have a great day!</span>
Pericardium or pericardial sac.
Hope This Helps!
Benedict's reagent is solution of copper sulfate,sodium carbonated,and sodium citrate
Answer:
36 ATPs
Explanation:
Cellular respiration starts with glycolysis wherein glucose is broken down into two molecules of pyruvate. The process of glycolysis forms two molecules of ATP by substrate-level phosphorylation for each glucose molecule. Both pyruvate molecules are converted into acetyl CoA to enter into the Kreb's cycle. Kreb's cycle forms two ATP molecules by substrate-level phosphorylation. NADH and FADH2 formed during glycolysis and Kreb's cycle are oxidized by the electron transport chain. This process also forms as many as 34 ATP molecules. If acetyl CoA is not formed, the total ATP gain per glucose will be only 2 ATP molecules (from glycolysis only) which is 38-2= 36 less than the total.
