Given the equation square root of 2x-1=7 solve for x and identify if it is an extraneous solution. I came up with the answer 25

Question

3 years ago

7

but is it an extraneous solution?

1 answer:

alexira [117] · Answer 1 · 2022-08-30T11:24:49+03:00

3 0

Step-by-step explanation:

To check if a solution is extraneous, simply plug it back into the original equation. If it works, then solution isn't extraneous.

√(2x−1) = 7

√(2(25)−1) = 7

√(50−1) = 7

√(49) = 7

7 = 7

So the solution isn't extraneous.