Given the equation square root of 2x-1=7 solve for x and identify if it is an extraneous solution. I came up with the answer 25
but is it an extraneous solution?
1 answer:
Step-by-step explanation:
To check if a solution is extraneous, simply plug it back into the original equation. If it works, then solution isn't extraneous.
√(2x−1) = 7
√(2(25)−1) = 7
√(50−1) = 7
√(49) = 7
7 = 7
So the solution isn't extraneous.
You might be interested in
Solution:
1) Simplify \frac{1}{6}x to \frac{x}{6}
y=\frac{x}{6}-2
2) Add 2 to both sides
y+2=\frac{x}{6}
3) Multiply both sides by 6
(y+2)\times 6=x
4) Regroup terms
6(y+2)=x
5) Switch sides
x=6(y+2)
Done!
Answer:
t = 18.8
Step-by-step explanation:
Hope this helped
please mar Brainliest
:)
Answer:
19)51.06
22)-3.08
25) 19.25 cost per visit.
Step-by-step explanation:
1 is B
2 is A
3 is E
4 is C
5 is D
Answer:
2^3=2×2×2=8
27=3×3×3 => cuberoot(27)=3
