Answer:
a. The mean of uniform distribution is (a+b)/2, where a and b are limits of the uniform distribution. So, mean is (0+12)/2 = 6 minutes
b. Standard deviation is (a-b)^2/12 = (0-12)^2/12 = (-12^2)/12 = 144/12 = 12
c. Prob (Wait for more than 5 min) = (12-5)/(12-0) = 7/12 = 0.5833
d. So, given he has waited for 2.8 minutes, what is prob that he will wait between 3.4 and 5.7 minutes
= (5.7 - 3.4) / ((12-2.8) - 0)
= (5.7 - 3.4) / (9.2 - 0)
= 2.3/9.2
= 0.25
e. 10% of all customers wait at least how long for the train?
10% of all customers wait for?
Since its a uniform distribution, people are uniformly spread. So, the 10% of people will be in the top 10% percentile group of waiting time which essentially means:
0.10 = (12-b)/(12-0)
0.10 = (12-b)/12
1.2 = 12 - b
b = 12 - 1.2
b = 10.8 minutes
So, 10% of all customers wait for at least 10.8 minutes for the train.
Answer:
Step-by-step explanation:
you started by expanding the bracket 3(2x+6) became 6x+18.\
Then you rearranged the equation so like terms were together.
You put brackets around the like terms so (27+18)+(6x+2x)
You added the first like terms (27+18)= 45
then you added the second like terms (6x+2x)= 8x
18 is 15% of 120 (onetwenty)
We have, 15% ×
x = 18 or, 15(100) ×
x = 18Multiplying both sides by 100 and dividing both sides by 15,
we have x = 18 × 100(15)
x = 120
Answer:
x = 12.26
Step-by-step explanation:
sin = opp/hyp
sin 50 = x/16
multiply both sides by 16
16 * sin50 = x
Use calculator
x = 12.256711089903649
Rounded
x = 12.26