7839 i think that’s right
Answer:
Juan has 32 dimes, 16 nickels and 8 quarters in his coin bank.
Step-by-step explanation:
Since in Juan's coin bank there are nickels (n), dimes (d), and quarters (q), and the number of quarters is one-quarter the number of dimes, and the number of nickels is twice the number of quarters, While the total value of the coins is $ 6.00, to find the number of each type of coin the following calculations must be performed:
Q = 1/4 D
N = 2Q = 1/2 D
D = D
20D + 10N + 5Q = X
20 x 0.10 + 10 x 0.05 + 5 x 0.25 = X
2 + 0.50 + 1.25 = X
3.75 = X
24D + 12N + 6Q = X
24 x 0.10 + 12 x 0.05 + 6 x 0.25 = X
2.40 + 0.60 + 1.50 = X
4.50 = X
32D + 16N + 8Q = X
32 x 0.10 + 16 x 0.05 + 8 x 0.25 = X
3.20 + 0.80 + 2 = X
6 = X
So, Juan has 32 dimes, 16 nickels and 8 quarters in his coin bank.
The answer is 671
3,039/9
671
671*9
3,039
Answer:
Answer is (A.)
Step-by-step explanation:
Answer:
1. 180
2. 300
3. 480
Step-by-step explanation:
1. Since 30% of 600 (or 0.3 * 600) = 180, the 1st blank is 180.
2. 50% of 600 (also easy to just think of one half {1/2}) = 300
3. Because 180 + 300 = 480
hope this helps:)
