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timurjin [86]
3 years ago
14

A driver can be jailed up to one year and fined up to $5,000 if he or she _________________.A. dumps litter on any public or pri

vate property or any waters in Georgia B. refuses to bring his or her vehicle to a stop when given a visual or an audible signal by a police officer C. rides in a house trailer while it is being towed by a vehicle on a highway
Mathematics
1 answer:
tia_tia [17]3 years ago
8 0

A driver can be jailed up to one year and fined up to $5,000 if he or she refuses to bring his or her vehicle to a stop when given a visual or an audible signal by a police officer.

Answer: Option B

<u>Step-by-step explanation:</u>

This Vehicle codes 2800.1 state a violation or avoidance of police. The rules as follows: "Any person who, while driving a motor vehicle and intentionally avoiding it, intentionally escapes or attempts to escape from a peace officer " Any driver who "intentionally fails or refuses to stop the vehicle or otherwise, an attempt to escape or prosecute the pursuing police officer when he receives a visual and audible signal to stop the vehicle.

"Visual and audible" signals include sirens, lights, hand signals and voice commands. You must have been able to hear and / or see these signals to be accused of escaping and attempting to escape from the police. This is a level II or level 3 crime, and any penalties for those fleeing or trying to avoid a police officer will depend on the scale of the crime they are suspected of.

  • Second-Degree Misdemeanour - in jail maximum of 2 years and fine max. of $5,000
  • Third-Degree Felony - in jail maximum of 7 years and fine max. of $15,000.
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The base of a pyramid has n sides write an expression for the number of faces of the pyramid
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6 0
4 years ago
Can someone answer these questions for me?
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3 0
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birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officia
Svetradugi [14.3K]

Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of  lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

z_1 = \dfrac{X-\mu}{\sigma}

-1.88 = \dfrac{X-3570}{500}

By cross multiply, we have:

-1.88 × 500 = X - 3570

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X = 2630 g

Hence, 2630 g is the required weight of birth   that differentiates the babies that needed special treatment from those that do not

6 0
3 years ago
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