120 * 45 % = 120 *0,45 = 54 £
120 -54 = 66 £
Answer:
Problem 1. <em>(19/2)b + 15</em>
Problem 2. <em>3/16</em>
Step-by-step explanation:
Question number 1
5/8 (16b+24) -1/2b =
= (5/8) * (16/1) * b + (5/8) * 24 - (1/2)b
= 10b + 15 - (1/2)b
= (20/2)b - (1/2)b + 15
= (19/2)b + 15
Question number 2
3/4 (16/64 + 12a) -9a =
= (3/4) * (16/64) + (3/4) * 12a - 9a
= (3 * 16)(4 * 64) + (3/4) * (12/1) * a - 9a
= (3 * 1)(4 * 4) + (3 * 12)/(4 * 1) * a - 9a
= 3/16 + (3 * 3)/(1 * 1) * a - 9a
= 3/16 + 9a - 9a
= 3/16
Answer:
500 pounds
Step-by-step explanation:
Let the pressure applied to the leverage bar be represented by p
Let the distance from the object be represented by d.
The pressure applied to a leverage bar varies inversely as the distance from the object.
Written mathematically, we have:
Introducing the constant of proportionality
If 150 pounds is required for a distance of 10 inches from the object
Therefore, the relationship between p and d is:
When d=3 Inches
The pressure applied when the distance is 3 inches is 500 pounds.
Alright, we're in the home stretch here :) All you need to remember is that i² = -1. Otherwise, it is the same as FOIL
(3-2i)(1+7i)
3-2i+21i-14i² ← Replace the i² with -1, then simplify like numbers
3+19i+14
17+19i or C
For the triangle, the shaded part, both the height and base are 12, so the area of it is:
1/2 (12 x 12) = 72
And the area of the whole square is 144
But what we’re looking for is the area of the unshaded region. So to find it, we’ll need to subtract the shaded from the total. So:
144 - 72 = 72
Thus, the area of the unshaded region is 72
