A = B+32
B = 5C
A = 5C+32
C has d dollars so replace d for c
A = 5d+32
Both of these conditions must be true in order for the assumption that the binomial distribution is approximately normal. In other words, if 
and 
then we can use a normal distribution to get a good estimate of the binomial distribution. If either np or nq is smaller than 5, then a normal distribution wouldn't be a good model to use.
side note: q = 1-p is the complement of probability p
Answer:
<u>Kevin's height increased 19.05%</u>
Step-by-step explanation:
Height of Kevin at the beginning of sixth grade = 4’10”
Height of Kevin at the end of ninth grade = 5’9”
What was the percentage of increase in Kevin height?
For answering this question, we should convert Kevin's heights to decimal number, this way:
1 feet = 12 inches
4’10” = 4 10/12 = 4.83
5’9” = 5 9/12 = 5.75
Now, let's use the Direct Rule of Three:
Height Percentage
4.83 100
5.75 x
***********************************
4.83x = 5.75 * 100
4.83x = 575
x = 575/4.83
x = 119.05
119.05 - 100 = 19.05
<u>Kevin's height increased 19.05%</u>
-5m - 6 >= 24
Add six on both sides
-5m >= 30
Divide by negative five on both sides
m >= -6
We assume w is the number of <em>inches</em> of width (as opposed to <em>feet</em> or some other measure). The length is 7 inches more than the width, so is w+7. The area is the product of these dimensions, and the problem statement tells us that area is greater than 375 in².
... w(w+7) > 375 . . . . . the inequality that can be used to find dimensions
