The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;
- Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.
- Maximum volume of the box is approximately 1048.6 in.³
<h3>How can the dimensions and volume of the box be calculated?</h3>
The given dimensions of the cardboard are;
Width = 18 inches
Length = 35 inches
Let <em>x </em>represent the side lengths of the cut squares, we have;
Width of the box formed = 18 - 2•x
Length of the box = 35 - 2•x
Height of the box = x
Volume, <em>V</em>, of the box is therefore;
V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x
By differentiation, at the extreme locations, we have;

Which gives;

6•x² - 106•x + 315 = 0

Therefore;
x ≈ 4.55, or x ≈ -5.55
When x ≈ 4.55, we have;
V = 4•x³ - 106•x² + 630•x
Which gives;
V ≈ 1048.6
When x ≈ -5.55, we have;
V ≈ -7450.8
The dimensions of the box that gives the maximum volume are therefore;
- Width ≈ 18 - 2×4.55 in. = 8.89 in.
- Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.
- The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³
Learn more about differentiation and integration here:
brainly.com/question/13058734
#SPJ1
Answer:
g(-4)=3
Step-by-step explanation:
g(x)=-x-1
g(-4)=-(-4)-1
g(-4)=4-1
g(-4)=3
9 = 3^2
Since 3 squared equals 9, that is how 9 as a power of the base 3 should be written.
Answer:
16 bicycles and 21 tricycles
Step-by-step explanation:
Both bicycles and tricycles have 1 set of handlebars. Bicycles have 2 wheels while tricycles have 3.
Using this information, set up a system of equations, where b is the number of bicycles and t is the number of tricycles:
b + t = 37
2b + 3t = 95
Solve by elimination by multiplying the top equation by -2:
-2b - 2t = -74
2b + 3t = 95
t = 21
Then, plug in 21 as t into one of the equations:
b + t = 37
b + 21 = 37
b = 16
So, there are 16 bicycles and 21 tricycles
Answer:
9 and 18
Step-by-step explanation:
