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3 years ago

HELP!!! A LOT OF POINTS!!!

Mathematics

1 answer:

Tpy6a [65]3 years ago

7 0

Answer: Last option.

Step-by-step explanation:

For this exercise you need to find the Discriminant.

The formula used to find the Discriminant, is the following:

$D=b^2-4ac$

In this case, given the Quadratic equation:

$6x^2-2x+7=0$

You can identify that:

$a=6\\b=-2\\c=7$

Knowing those values, you must substitute them into the formula and then you must evaluate in order to find the Discriminant.

You get that this is:

$D=(-2)^2-4(6)(7)\\\\D=-164$

By definition, if:

$D$

Then the Quadraitc equation has 2 nonreal solutions.

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Jasmine makes balloon animals at community events. In 240 minutes, she uses 144 balloons to make 48 animals. How many balloons a

Norma-Jean [14]

Answer:

he uses 23 balloons for every 28 events.

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3 years ago

Math help plz! Giving brainlist :D

Yuri [45]

-x^2+4x-4

dy/dx=-2x+4, d2y/dx2=-2

Since acceleration is a constant negative, when dy/dx, velocity, equals zero, it is at the absolute maximum value for f(x).

dy/dx=0 when -2x+4=0, 2x=4, x=2

f(2)=-x^2+4x-4=-4+8-4=0

So there is a maximum of zero

...

.5x^2+8x+5

dy/dx=x+8, d2y/dx2=1

Since d2y/dx2, acceleration is a constant positive, when dy/dx=0, it is at the point when f(x) is at an absolute minimum.

dy/dx=0 when x+8=0, x=-8

f(-8)=.5x^2+8x+5=32-64+5=-27

So there is a absolute minimum of -27

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-2(x+1)^2+5

dy/dx=-4(x+1)=-4x-4, d2y/dx2=-4

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3 years ago

Yesterday I sold 64 icecreams. This morning I sold 80 icecreams. With what percentage did my sales increase?

s2008m [1.1K]

The sales increased by 25%

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3 years ago

Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi

notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{68-74}{6}$

$z=\frac{-6}{6}=-1$

Now let us find z-score for 86.

$z=\frac{86-74}{6}$

$z=\frac{12}{6}=2$

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,

$P(-1$