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ololo11 [35]
3 years ago
13

A book had a length of 5 inches and a width of 10 inches what is the area of the book

Mathematics
1 answer:
jeka943 years ago
3 0
50ft squared
{50}^{2}
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)A manufacturer packages 250 sheets of paper in every box. How many boxes are needed to package 3,000 sheets of paper? A) 10 (в
VLD [36.1K]

Answer: D.

Step-by-step explanation:

3000/250=120

6 0
2 years ago
4. The system of equations 3x – 6y = 20 and 2x – 4y = 3 is
expeople1 [14]
3x - 6y = 20
-6y = -3x + 20
y = 1/2x - 20/6.....slope = 1/2...y int = -20/6 = -10/3

2x - 4y = 3
-4y = -2x + 3
y = 1/2x - 3/4..slope = 1/2...y int = -3/4

same slope, different y int = parallel lines = no solution = inconsistent
6 0
3 years ago
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What is the prime factorization of 420?
a_sh-v [17]

we have the factors 2 x 2 x 3 x 5 x 7 = 420. It can also be written in exponential form as 22 x 31 x 51 x 71.

Step-by-step explanation:

6 0
2 years ago
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Evaluate the integral. 3 2 t3i t t − 2 j t sin(πt)k dt
sveta [45]

∫(t = 2 to 3) t^3 dt

= (1/4)t^4 {for t = 2 to 3}

= 65/4.

----

∫(t = 2 to 3) t √(t - 2) dt

= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2

= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du

= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}

= 26/15.

----

For the k-entry, use integration by parts with

u = t, dv = sin(πt) dt

du = 1 dt, v = (-1/π) cos(πt).


So, ∫(t = 2 to 3) t sin(πt) dt

= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt

= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]

= 5/π + 0

= 5/π.

Therefore,

∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.

3 0
3 years ago
Which of the following represents the ratio of the short leg to the hypotenuse
inn [45]
I believe the answer is C
3 0
3 years ago
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