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kodGreya [7K]
3 years ago
11

Triangle A B C is reflected and then dilated to form smaller triangle A double-prime B double-prime C double-prime Which transfo

rmations could have occurred to map △ABC to △A"B"C"? a rotation and a dilation a rotation and a reflection a reflection and a dilation a translation and a dilation
Mathematics
1 answer:
Gnoma [55]3 years ago
6 0

Answer:

a reflection and a dilation

Step-by-step explanation:

in the wording, it was stated that the triangle was reflected then dilated.

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Which is the correct algebraic representation of the transformation displayed on the graph?
zheka24 [161]

Answer:

B

Step-by-step explanation:

Its correct tm

4 0
3 years ago
Read 2 more answers
For questions 8 – 10, answer the questions about tangent-tangent angles.
olchik [2.2K]

Answer:

m(arc ZWY) = 305°

Step-by-step explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

                                                   = \frac{1}{2}(220-140)

                                                   = \frac{1}{2}(80)

                                                   = 40°

9). Following the same rule as above,

Angle formed between two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

125 = \frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]

250 = [m(\text{arc ZWY})-m(\text{arc ZY})]

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) = \frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])

                          = \frac{1}{2}(254-106)

                          = \frac{148}{2}

                          = 74°

4 0
2 years ago
What is the area of a triangle whose base is 14 m and whose height is 22 m?
Ivanshal [37]

Base times height divided by 2 is the area. So 14 times 22 is 308 and divided by 2 is 154 so that is your answer. I hope this helps. Could I possibly get brainliest?

4 0
3 years ago
Find m∠STU and m∠TUA
PIT_PIT [208]

Answers:

  • angle STU = 65 degrees
  • angle TUA = 123 degrees

=========================================================

Explanation:

Let's find the expression for angle TUS in terms of x

Angle TUA has the expression 11x+2. It will add to angle TUS to get 180 degrees

(angle TUS) + (angle TUA) = 180

angle TUS = 180 - (angle TUA)

angle TUS = 180 - (11x + 2)

angle TUS = 180 - 11x - 2

angle TUS = -11x + 178

Now focus on the interior angles of triangle TUS. We have these three angles

  • T = 5x+10
  • U = -11x+178
  • S = 58

For any triangle, the interior angles always add to 180, so,

T+U+S = 180

(5x+10) + (-11x+178) + (58) = 180

(5x-11x) + (10+178+58) = 180

-6x + 246 = 180

-6x = 180-246

-6x = -66

x = -66/(-6)

x = 11

Use this x value to find the angle measures we're after:

  • angle STU = 5x+10 = 5*11+10 = 55+10 = 65 degrees
  • angle TUA = 11x+2 = 11*11+2 = 121+2 = 123 degrees

--------------------------

As an alternative route, you can apply the remote interior angle theorem. This says that adding two interior angles leads to the exterior angle that isn't adjacent to either one.

In this case, we would say

(angle STU) + (angle TSU) = angle TUA

that leads to the equation

(5x+10) + (58) = 11x+2

Solving this should lead to x = 11 to generate the angles mentioned earlier.

6 0
3 years ago
The circumference of a
timama [110]

9514 1404 393

Answer:

  • 160,000 m²
  • 16 ha

Step-by-step explanation:

The side length of a square is 1/4 of the perimeter, so the side length of the square orchard is (1600 m)/4 = 400 m.

The area of a square is the square of the side length, so the area of the orchard is (400 m)² = 160,000 m².

A hectare is 10,000 m², so the area of the orchard in hectares is ...

  16·(10,000 m²) = 16 ha

3 0
3 years ago
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