Alice and Bob arrange to meet for lunch on a certain day at noon. However,neither is known for punctuality. They both arrive ind ependently at uniformly distributedtimes between noon and 1 pm on that day. Each is willing to wait up to 15 minutes forthe other to show up. What is the probability they will meet for lunch that day? "slader"
1 answer:
Answer:
probability of there meeting = 15/(60-15) = 15/45 = 0.333 = 33%
Step-by-step explanation:
favorable event = +- 15 minutes
total time they can eat launch is between noon and 1pm = 60minutes
they are both known for non punctuality, that means they cant meet up at 12noon, let assume 15minutes pass noon.
probability of there meeting = 15/(60-15) = 15/45 = 0.333 = 33%
which is probably saying they will not meet for lunch that day.
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