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Alinara [238K]
3 years ago
13

What is the y-intercept of this graph?

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

Input work is the work done on a machine as the input force acts through the input distance. This is in contrast to output work which is a force that is applied by the body or system to something else. Output work is the work done by a machine as the output force acts through the output distance.Jan 15, 20jsusbwhshhee sbshd she dhd dhd did dhd dhe dyebduebd

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PLEASE HURRY!!!!
Aleksandr [31]

Answer:

The answer is 40

Step-by-step explanation:

The reason for this is because. . .

(-1,-4) , (3,6)

so you have count from -1 to 3 and u will get 4, because if you can put (-1,-4) and (3,6) on a graph. If you did that then u must count horizantolly from -1 to 3 since they are on the x-axis. In the end you will get 4 since 3 minus -1 is 4. Also if your counting horizantally then that's ur width.

width = 4

To find the length, it is very simple. Subrtract 6 from -4 and you will get 10. And since the y-axis is being counted vertically, that is your length.

length = 10

To find the area, u have to do width times length so in this case you have to do 4 time 10 and you will get 40.

area = 40

8 0
3 years ago
Which of the following statements about the image below is true?
Orlov [11]

Answer:

d. Line UR and Line VW are parallel

Step-by-step explanation:

If they were to continue going straight, they would not touch, making them parallel.

I hope this helps!

8 0
3 years ago
Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2
Basile [38]

The Laplace transform of the given initial-value problem

y' 5y = e^{4t}, y(0) = 2 is  mathematically given as

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is  mathematically given as

&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}

\begin{aligned}&\text { Let } \frac{2 s-7}{(s+5)(s-4)}=\frac{a_{0}}{s-4}+\frac{a_{1}}{s+5} \\&\Rightarrow 2 s-7=a_{0}(s+s)+a_{1}(s-4)\end{aligned}

put $s=-s \Rightarrow a_{1}=\frac{17}{9}$

\begin{aligned}\text { put } s &=4 \Rightarrow a_{0}=\frac{1}{9} \\\Rightarrow \quad y(s) &=\frac{1}{9(s-4)}+\frac{17}{9(s+s)}\end{aligned}

In conclusion, Taking inverse Laplace tranoform

L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

Read more about Laplace tranoform

brainly.com/question/14487937

#SPJ4

6 0
2 years ago
Compare the decimal by writing &lt;,&gt; or = on the space provided.
Svet_ta [14]

Answer:

1. <  2. < 3. > 4. = 5. >

Step-by-step explanation:

3 0
3 years ago
What is my mystery number???
emmasim [6.3K]

Answer:

48 or 66

Step-by-step explanation:

Even numbers have digits that add to 12: 39, 48, 57, 66, 75.

48 and 66 are even and add up to 12.

5 0
3 years ago
Read 2 more answers
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