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babunello [35]
3 years ago
11

When two lines are cut by a transversal, if the alternate interior angles are equal in measure, then the lines are parallel.

Mathematics
2 answers:
Ray Of Light [21]3 years ago
6 0

Answer:

When two lines are cut by a transversal, if the alternate interior angles are equal in measure, then the lines are always parallel.

Step-by-step explanation:

Given that when two lines are cut by a transversal, if the alternate interior angles are equal in measure,

then we have to tell lines are parallel or not.

Alternate interior angles are the angles formed on the inner side of two lines but on the opposite sides.

The above two angles are equal if two lines which cut by transversal are parallel.

Hence, when two lines are cut by a transversal, if the alternate interior angles are equal in measure, then the lines are always parallel.

 

avanturin [10]3 years ago
3 0
They are always parallel
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A partir del 1.° de diciembre, un camión de helados visita la calle de Sara cada 3 días y la calle de Ema cada 5 días. ¿Cuáles s
777dan777 [17]

Answer:

Los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.

Step-by-step explanation:

Los múltiplos de un número son todos los posibles resultados de multiplicar ese número por todos y cada uno de los números naturales.

Es decir, los múltiplos de un número natural son los números naturales que resultan de multiplicar ese número por otros números naturales.

El conjunto de los múltiplos de un número determinado (salvo el cero) es infinito, pues existen infinitos naturales para multiplicar.

Para determinar cuáles son los primeros 2 días que el camión visita ambas calles el mismo día, debes encontrar los múltiplos de 3 y 5:

múltiplos de 3: 3; 6; 9; 12; 15; 18; 21; 24; 27; 30

múltiplos de 5: 5; 10; 15; 20; 25; 30; 35; 40; 45; 50

Podes observar que los 2 primeros números comunes o que coinciden entre los múltiplos de 3 y 5 son 15 y 30. Esto quiere decir que <u><em>los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.</em></u>

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3 years ago
You want to place a towel bar that is 10 1⁄4 inches long in the center of a door that is 26 1⁄3 inches wide. How far should you
attashe74 [19]
The bar should be 8 1/24 from the each edge of the door.

We need to subtract 10 1/4 from 26 1/3 to get the fraction of the space not covered by the towel bar. 
We also need to divide the difference by 2 because we placed the towel bar in the center of the door.

1st we need to convert the mixed fractions into fractions to perform subtraction.
26 1/3 = ((26*3)+1)/3 = 79/3
10 1/4 = ((10*4)+1)/4 = 41/4

Steps in Subtracting Fractions
Step 1. Make sure the denominator is the same. 3 and 4 are the denominators, they are not the same but they are factor of 12. So,
79/3 must be multiplied by 4 = 79 * 4 / 3 * 4 = 316 / 12
41/4 must be multiplied by 3 = 41 * 3 / 4 * 3 = 123 / 12

Step 2. Subtract the numerators and place them above the common denominator
316/12 - 123/12 = 316 - 123 / 12 = 193 / 12

Before we can simplify the fraction, we must divide it by two to get the measurement of each edge of the door.

Steps in dividing fractions.
Step 1. Get the reciprocal of the 2nd fraction.
1st fraction : 193 / 12
2nd fraction : 2 /1  ⇒ reciprocal 1/2

Step 2. Multiply the 1st fraction to the reciprocal of the 2nd fraction
193 / 12 * 1/2 = 193 * 1 / 12 * 2 = 193 / 24

Step 3. Simplify the fraction.
193 / 24 = 8 1/24
8 0
3 years ago
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