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2 years ago

Find the area of a triangle with base of 10 inches and altitude to the base of 16 inches.

Mathematics

1 answer:

Ostrovityanka [42]2 years ago

4 0

(10*16)/2
160/2=80
The area is 80.

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Answer:

We conclude that:

$\left(x-8\right)^2+16=x^2-16x+80$

Step-by-step explanation:

Given the equation

$\left(x-8\right)^2\:+\:16$

First, solve (x - 8)²

Apply Perfect Square formula: (a - b)² = a² - 2ab + b²

$a=x,\:\:b=8$

$\left(x-8\right)^2=x^2-2x\cdot \:\:8+8^2$

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so the expression becomes

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Therefore, we conclude that:

$\left(x-8\right)^2+16=x^2-16x+80$

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