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olchik [2.2K]
3 years ago
8

Josh examines the expression of 5-m/5m where m is greater than z.

Mathematics
1 answer:
inysia [295]3 years ago
8 0

Answer:

what is z

Step-by-step explanation:

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. The selling price of 15 articles is Rs 1,500 at a gain of 8%. Find C.P of each article<br>​
Andru [333]

<u>Rs. 92.59</u> is each article's CP

Step-by-step Explanation:-

As per conditions given,

1500 \div 15 \div (1 + 8%)

=  > 100 \div 1.08

=  > approx. \: 92.59

Hence, the CP of each article is <u>Rs. 92.59</u>

3 0
2 years ago
Subtract 9x^2 - 7x from -4x^2 + 6
Rzqust [24]

Answer:

13x^2 - 7x + 6

Step-by-step explanation:

(9x^2 -7x) - 1(-4x^2 + 6)

(9x^2 -7x) + 4x^2 +6

9x^2 - 7x + 4x^2 + 6

(9x^2 + 4x^2) - 7x + 6

13x^2 - 7x + 6

8 0
4 years ago
How much is Jonah's income tax for the year?
Juliette [100K]
Jonah makes 85,740, which is at least 85,650 but less than 178,650, his tax is 28%. All you have to do is multiply 85,740 by 28% a.k.a .28 and you should get 24,007.2 which is Jonah’s income tax for the year.
3 0
3 years ago
A grab bag contains 4 football cards and 6 basketball cards. An experiment consists of taking one card out of the bag, replacing
Zinaida [17]
Total Number of cards = 4 + 6 = 10
Number of Football cards = 4
Number of Basketball cards = 6

Probability of choosing a football card = 4/10 = 0.4
Since this card is replaced, the total number of cards will remain the same.

Probability of selecting a basketball card = 6/10 = 0.6

Since, the two events are independent, the probability of selecting a football and a basketball card will be the product of two probabilities we calculated. 

Thus, probability of selecting a football card and then a basketball card = 0.4 x 0.6 = 0.24
5 0
3 years ago
Read 2 more answers
A bulletin board measuring 28 dm long was divided among three subject areas in the ratio 2:2:3. How much space was alothed for e
Sphinxa [80]

Answer: Space was alloted for each subject is 8 dm, 8 dm, 12 dm.

Explanation:

Since we have given the length of bulletin board =28 dm

Let the share of three subject areas be 2x,2x,3x

According to question,

2x+2x+3x=28\\7x=28\\x=\frac{28}{7}\\x=4dm

so x=4 dm

Now,

Space was alloted for each subject is given as below:

First subject =2x=2\times 4=8 dm

Second subject =2x=2\times 4=8 dm

Third subject =3x=3\times 4=12 dm

4 0
3 years ago
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