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3 years ago

A circle has a radius of 11 in. Find the length s of the arc intercepted by a central angle of 11°.

Mathematics

1 answer:

Travka [436]3 years ago

7 0

Answer:

Step-by-step explanation:

11 degrees to radians: 1 degree =57.296 radians

L = (11 degrees)/(57.296) x (11 in) = 2.111848 in

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C) Millennium Park has an outdoor concert theater. Before a concert, the area reserved for special seating is roped off in the s

Trava [24]

Answer:

The converse of Pythagorean Theorem states:

If the square length of the longes side of a triangle is equal to the sum of the squares of the other two sides, then it's a right triangle.

We use the converse of Pythagorean Theorem to prove that a triangle is a right triangle. It's like the inverse use of the theorem. Often, this theorem is used to find the length of a side of a triangle when we already know it's a right triangle. However, when we don't know that is a right triangle, we use the converse to prove it.

Step-by-step explanation:

I did it Edge 2021. Good Luck:)<3

3 0

3 years ago

If sin square theta = 0.75, then cos =

sergeinik [125]

Answer:

$\cos\theta=\pm0.5$

Step-by-step explanation:

Given:

$\sin^2\theta=0.75$

To find $\cos\theta$

Using trigonometric relations for sums and differences of squares of the ratios.

We know:

$\sin^2\theta+\cos^2\theta =1$

Plugging in $\sin^2\theta=0.75$ in the above relation.

$0.75+\cos^2\theta =1$

Subtracting both sides by 0.75.

$0.75+\cos^2\theta-0.75 =1-0.75$

$\cos^2\theta =0.25$

Taking square root both sides.

$\sqrt{\cos^2\theta} =\sqrt{0.25}$

∴ $\cos\theta=\pm0.5$ (Answer)

6 0

3 years ago

Polynomial equation when zeros are -4, -2, 1, 4

jek_recluse [69]

<h2>The required poynomial equation is $x^{4}+x^{3}-18x^{2}-16x+32$ .</h2>

Step-by-step explanation:

Given,

The zeros of the polynomial are - 4, - 2, 1 and 4

To find, the polynomial equation = ?

We know that,

The polynomial equation = (x - A)(x - B)(x - C)(x - D)

= (x + 4)(x + 2)(x - 1)(x - 4)

= [(x + 4)(x - 4)] [(x + 2)(x - 1)]

= ( $x^{2}-16$ )( $x^2-x+2x-2$ )

= ( $x^{2}-16$ )( $x^2+x-2$ )

= $x^{4}+x^{3}-2x^{2}-16x^{2}-16x+32$

= $x^{4}+x^{3}-18x^{2}-16x+32$

Thus, the required poynomial equation is $x^{4}+x^{3}-18x^{2}-16x+32$ .

4 0

3 years ago

Need help please!!!!

ArbitrLikvidat [17]

Given : A inequality is given to us . The inequality is 19 ≥ t + 18 ≥ 11 .

To Find : The correct option between the given ones . To write the compound inequality with integers .

Solution : The given inequality to us is 19 ≥ t + 18 ≥ 11 . Let's simplify them seperately .

$\red{\tt Case\:1}$

⇒ 19 ≥ t + 18 .

⇒ t + 18 ≤ 19 .

⇒ t ≤ 19 - 18 .

⇒ t ≤ 1 = 1 ≥ t . ..................(i)

$\red{\tt Case\:2}$

⇒ t + 18 ≥ 11 .

⇒ t ≥ 11 - 18.

⇒ t ≥ -7 . ....................(ii)

On combing (i) & (ii) .

$\Large\boxed{\green{\bf \red{\longmapsto} 1 \geqslant t \geqslant -7 }}$

This means that t is less than or equal to 1 but greater than or equal to (-7) .

4 0

3 years ago

(28 POINTS)

cestrela7 [59]

Answer:

(a) $-\sqrt{10}y$

(b) $-\sqrt{3}y$

Step-by-step explanation:

(a) $\sqrt{10y^{2}}$ can also be written as $\sqrt{10}$ x $\sqrt{y^{2}}$

the $\sqrt{y^{2}}$ = ± y

Therefore :

$\sqrt{10y^{2}}$ = ± $\sqrt{10}y$

since it was given that y < 0 , then the factor will be $-\sqrt{10}y$

(b) $\sqrt{3y^{2}}$ can also be written as : $\sqrt{3}$ x $\sqrt{y^{2}}$

Therefore , one of the factor is $-\sqrt{3}y$

3 0

3 years ago