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3 years ago

2x^3-4x^2+6x-12 / 2x+2

Mathematics

1 answer:

Brrunno [24]3 years ago

3 0

Answer:

2 • (x2 - 3) • (x + 2)

Step-by-step explanation:

(A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

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2. Solve x - 19 <81. Then graph the solution.

mr_godi [17]

Answer:

x<100

Step-by-step explanation:

The given equation is :

x-19<81

Adding 19 to both sides of the equation.

x-19+19<81+19

x<100

It means the solution of the given equation is less than 100. Hence, the attached figure shows the graph for the given equation.

4 0

3 years ago

Write the out the equation -52 times the difference between a number and 97 is equal to the number plus 39

denis-greek [22]

-52(x-97)=39
we get the answer when u solve the equation

5 0

3 years ago

Here are the dimensions of the oven tray Jenny bakes the cakes on 600mm by 500mm. Each cake tin is 25 cm in diameter. How many c

storchak [24]

Given:
2 shapes: rectangle (tray) and circle (cake tin)

We need to find the area of each shape.

We need to convert mm to cm. 1mm = 0.1cm
600mm x 0.1cm/1mm = 60cm
500mm x 0.1cm/1mm = 50cm

Area of the Tray = 60cm * 50cm = 3,000cm²

Area of the cake tin = π r²
r = d/2 = 25/2 = 12.5cm

Area of the cake tin = 3.14 * (12.5cm)²
Area of the cake tin = 3.14 * 156.25cm²
Area of the cake tin = 490.625cm²

Area of the tray ÷ Area of the cake tin = number of cake tins that fit
3,000cm² ÷ 490.625cm² = 6.11 or 6 cake tins.

Only 6 cake tins Jenny can fit on the oven tray at one time.

7 0

4 years ago

A particle moves along line segments from the origin to the points (2, 0, 0), (2, 4, 1), (0, 4, 1), and back to the origin under

Shkiper50 [21]

The work is equal to the line integral of $\vec F$ over each line segment.

Parameterize the paths

from (0, 0, 0) to (2, 0, 0) by $\vec r_1(t)=t\,\vec\imath$ with $0\le t\le2$ ,
from (2, 0, 0) to (2, 4, 1) by $\vec r_2(t)=2\,\vec\imath+4t\,\vec\jmath+t\,\vec k$ with $0\le t\le1$ ,
from (2, 4, 1) to (0, 4, 1) by $\vec r_3(t)=(2-t)\,\vec\imath+4\,\vec\jmath+\vec k$ with $0\le t\le2$ , and
from (0, 4, 1) to (0, 0, 0) by $\vec r_4(t)=(4-4t)\,\vec\jmath+(1-t)\,\vec k$ with $0\le t\le1$

The work done by $\vec F$ over each segment (call them $C_1,\ldots,C_4$ ) is

$\displaystyle\int_{C_1}\vec F\cdot\mathrm d\vec r_1=\int_0^2\vec0\cdot\vec\imath\,\mathrm dt=0$

$\displaystyle\int_{C_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(t^2\,\vec\imath+24t\,\vec\jmath+32t^2\,\vec k)\cdot(4\,\vec\jmath+\vec k)\,\mathrm dt=\int_0^1(96t+32t^2)\,\mathrm dt=\frac{176}3$

$\displaystyle\int_{C_3}\vec F\cdot\mathrm d\vec r_3=\int_0^2(\vec\imath+(24-12t)\,\vec\jmath+32\,\vec k)\cdot(-\vec\imath)\,\mathrm dr=-\int_0^2\mathrm dt=-2$

$\displaystyle\int_{C_4}\vec F\cdot\mathrm d\vec r_4=\int_0^1((1-t)^2\,\vec\imath+2(4-4t)^2\,\vec k)\cdot(-4\,\vec\jmath-\vec k)\,\mathrm dt=-2\int_0^1(4-4t)^2\,\mathrm dt=-\frac{32}3$

Then the total work done by $\vec F$ over the particle's path is 46.

8 0

4 years ago

What Percent Of 36 Is 96? ( How Do You Solve It ) Answer Not Neccessary

gtnhenbr [62]

You would divide 36 by 96 and multiply that answer by 100.

36÷96×100
=0.375×100
=37.5%

6 0

3 years ago