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DanielleElmas [232]
2 years ago
9

Please help.

Mathematics
2 answers:
ddd [48]2 years ago
6 0

Answer:

The\ brother's\ present\ age= 4\ years\\The\ sister's\ present\ age=8\ years

Step-by-step explanation:

Let\ the\ brother's\ present\ age\ be\ x\\Hence\ we\ are\ given,\\His\ sister's\ present\ age=(2x)\\Now,\\The\ brother's\ age\ before\ two\ years=(x-2)\\The\ sister's\ age\ before\ two\ years=3(x-2)\\Also,\\His\ sisters\ age\ before\ two\ years=2x-2\\Hence,\\3(x-2)=2x-2\\3x-6=2x-2\\3x-2x=6-2\\x=4\\Hence,\\The\ brother's\ present\ age= 4\ years\\The\ sister's\ present\ age=2x=2*4=8\ years

AnnZ [28]2 years ago
4 0

Answer:

The sister's present age is 8 years old, and the brother's present age is 4 years old.

Step-by-step explanation:

Let b = present age of the brother, s = present age of the sister

s-2 = (b-2) × 3

s-2 = 3b - 6

s = 3b - 4

s = b × 2

= 2b

sb-4 = 2b  (proved from above equations)

b = 4

\because s = 3b - 4

\therefores = 3×4 - 4

= 8

\therefore the brother's present age is 4 years old, and the sister's present age is 8 years old.

Hope this helps :)

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