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3 years ago

10

A flashlight has 8 batteries, 3 of which are defective. If 2 are selected at random without replacement, find the probability th

at both are defective.
3/8

3/28

2/5

1/8

1 answer:

sweet-ann [11.9K]3 years ago

4 0

3/8 is the answer because you subtract 3-8 to get 5, then subtract another 2 for the 2 batteries that were selected randomly.

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Step-by-step explanation:

For this case we have the following two points given:

$x_1 = 5, x_2 =11, y_1 =9, y_2 = -3$

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And the best answer for this case would be :

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