3 years ago

The square of a positive number is 24 more than 5 times a number. What is the value of the number?

Mathematics

1 answer:

Mars2501 [29]3 years ago

8 0

X² = 24+5y

y=5 and x=7

You might be interested in

Please help me asap !!!

Fynjy0 [20]

Total of all Gross Wages minus all pre- tax deductions. Total of all Pre-Tax and. Post-Tax deductions. For this pay period.

6 0

3 years ago

Whats 15-b=4b-5(5-3)

Gala2k [10]

15-b=4b-5(5-3)

Multiply the bracket by -5

(-5)(5)=-25

(-5)(-3)=15

15-b=4b-25+15

15-b=4b-10

Move 15 to the other side

Sign changes from +15 to -15

15-15-b=4b-10-15

-b=4b-25

Move 4b to the other side.

-b-4b=4b-4b-25

-b-4b=-25

-5b=-25

divide both sides by -5

-5b/-5=-25/-5

Answer: b=5

5 0

3 years ago

Who has insta im bored

nlexa [21]

wish i did, i'm bored as well

3 0

3 years ago

Read 2 more answers

What is the solution set for 4x+ 9 <17?

Natali5045456 [20]

Answer:

The awnser is d i think

7 0

3 years ago

Read 2 more answers

¿cual es el perimetro total de un paralelogramo obicuo cuya base mide 2∛54x² cm , y cuyo lado oblicuo mide 3∛54x²?

Step2247 [10]

Answer:

$p=10\sqrt[3]{54}x^2$

Step-by-step explanation:

We are given parallelogram

Since, two opposite sides of any parallelogram are always equal

Let's assume first side =a

second side =b

so, we get

$a=2\sqrt[3]{54}x^2$

$b=3\sqrt[3]{54}x^2$

now, we can find perimeter

perimeter=2a+2b

so, we get

$p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)$

we can simplify it

$p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2$

$p=10\sqrt[3]{54}x^2$ ................Answer

6 0

3 years ago

Read 2 more answers