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77julia77 [94]
3 years ago
9

Un automóvil corre a 120 kilómetros por hora y otro a 80 kilómUetros por hora; si deben recorrer 960 kilómetros, ¿con cuántas ho

ras de diferencia llega el primero del segundo?
Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0

Answer:

4 hours

Step-by-step explanation:

The speed of the first car is

v_1 = 120 km/h

While the speed of the second car is

v_2=80 km/h

The time it takes for each car to cover a distance d is

t=\frac{d}{v}

where

d = 960 km is the total distance covered

For car 1, the time taken is:

t_1=\frac{960}{120}=8 h

For car 2, the time taken is:

t_2=\frac{960}{80}=12 h

Therefore, the difference in time is:

\Delta t =t_2-t_1 =12 -8 = 4 h

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Which graph shows the solution to this system of inequalities?<br> y&gt;-1/3x+1<br> y&gt;2x-3
Mademuasel [1]

Given:

The system of inequalities is:

y>-\dfrac{1}{3}x+1

y>2x-3

To find:

The graph of the given system of inequalities.

Solution:

We have,

y>-\dfrac{1}{3}x+1

y>2x-3

The related equations are:

y=-\dfrac{1}{3}x+1

y=2x-3

Table of values for the given equations is:

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   0                             1                              -3

   3                             0                              3

Plot (0,1) and (3,0) and connect them by a straight line to get the graph of y=-\dfrac{1}{3}x+1.

Similarly, plot (0,-3) and (3,3) and connect them by a straight line to get the graph of y=2x-3.

The signs of both inequalities are ">". So, the boundary line is a dotted line and the shaded region or each inequality lie above the boundary line.

Therefore, the graph of the given system of inequalities is shown below.

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