What is 694 divided by 41 and what is the remainder please help thank you
2 answers:
We can use long division in finding the remainder.
Place the divisor which is 41, outside the long division sign, and 694 under the long division sign as shown in the diagram.
41 goes into 694 16 times.
Write the 16 on top of the long division sign.
Multiply the 16 by 41, to obtain 656
Write the 656 below the 694 as in the diagram.
Subtract 656 from 694 to obtain 38.
Since 41 is more than 38 , we cannot proceed.
Hence,
Therefore the remainder is 38
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Answer:
Step-by-step explanation:
To find the we must use the cosine theorem.
The cosine theorem says that:
In this case:
So
I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.
Answer: n² - 3n - 20 = 0
That doesn't factor so there is no integer n solution.
That means there are no polygons with 10 diagonals.