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Sedbober [7]
3 years ago
13

WHAT IS THE SQUARE ROOT OF 225

Mathematics
2 answers:
gladu [14]3 years ago
7 0
It is twenty five; 25

ludmilkaskok [199]3 years ago
3 0
The square root of 225 is 15 :)
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Find the slope of the line that passes trough(5,-10) and (5,-4)
Gwar [14]

Answer:

Answer Undefined

Step-by-step explanation:

This line is a vertical line because the x coordinate is the same on both points (5 is the x coordinate in both points). Vertical line's slopes are undefined because they go from up to down.

3 0
3 years ago
Read 2 more answers
An appliance company uses the function f(h) = 40h + 120 to calculate the total repair bill, f(h), for h number of hours worked.
Verdich [7]

Answer:

fh. = 40h + 120,  fh. = $200

200 = 40h + 120

200 - 120 = 40h

80 = 40h

80/40  = h

 2 = h

h = 2 hours.

Step-by-step explanation:

4 0
3 years ago
the odds of rolling a certain number on a single die is 1 chance in 6 rolls. in course of a game, someone rolled 3 fives. accord
Zina [86]

Answer:

18

Step-by-step explanation:

The expected value is the probability times the frequency.

3 = 1/6 × n

n = 18

Note: the use of the word "odds" is very misleading here.  Odds are the ratio of number of successes to number of failures:

S / F

Probability is the ratio of number of successes to number of all outcomes:

S / (S + F)

So the probability of rolling a 5 is 1/6.  The odds of rolling a 5 is 1/5.

Furthermore, the word "must" is also incorrect.  The player didn't <em>have</em> to roll 18 times.  They could have rolled three times and gotten a 5 each time.  Or they could have rolled 100 times.  18 is simply the most <em>likely </em>number of rolls needed to get three 5's.

6 0
3 years ago
A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

5 0
3 years ago
Help my dudes its a photooooooooo
andrew-mc [135]

Answer: It would be option B (13 over 5).

Step-by-step explanation: Step 1) Subtract 15 from both sides, 5x=13. Step 2) Divide both sides by 5, x=13 over 5. Hope this helps bub <3

6 0
3 years ago
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