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castortr0y [4]
3 years ago
5

Solution. 6) -162-5-X 8 9 10 11 12 14 15 16 17 18

Mathematics
1 answer:
statuscvo [17]3 years ago
7 0
X ≥ 11 is the answer
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A two and a half pound of grass seeds covers one eight of an acre.
frez [133]

Answer: 60 lbs?

Step-by-step explanation:

3 0
2 years ago
A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time
user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

a(t) = 24t + 2

Velocity:

v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

v(t) = 12t^{2} + 2t + 13

Position:

s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K

Since s(0) = 3

s(t) = 4t^{3} + t^{2} + 13t + 3

What is its position at time t=5?

This is s(5).

s(t) = 4t^{3} + t^{2} + 13t + 3

s(5) = 4*5^{3} + 5^{2} + 13*5 + 3

s(5) = 593

It's position at time t = 5 is 593.

3 0
3 years ago
Look at the table below. Plot and label points M and N on the coordinate
marta [7]
M = (1,4)
N = (5,2)

For M, you simply move to 1 on the x axis abs for 4 you move on the y axis. Same does for N, for 5 you move on the x axis and for 2 you move on the y axis.
6 0
3 years ago
In the figure,Line x is parallel to line y. identify the angles congruent to angle 3
san4es73 [151]

Answer:

For example, slide ∠ 1 down the transversal and it will coincide with ∠2. are equal in measure. If two parallel lines are cut by a transversal, the corresponding angles are congruent. If two lines are cut by a transversal and the corresponding angles are congruent, the lines are parallel.

Step-by-step explanation:

8 0
2 years ago
Helppp me pleaseee!!!!!!!
kenny6666 [7]

Answer:

V=πr2h

3=π·72·9

3≈461.81412

Step-by-step explanation:

Mark me the brainliest PLZ.

7 0
3 years ago
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