3 years ago

Evaluate: 3² × (-2)³ × 5

Mathematics

1 answer:

Elan Coil [88]3 years ago

3 0

Answer:

Step-by-step explanation:

Thank you ☺️☺️

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Answer:

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Step-by-step explanation:

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RideAnS [48]

$\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}$

We know that : (a - b)(a + b) = a² - b²

$\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}$

We know that : 1 - sin²x = cos²x

$\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}$

$\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}$

$\implies \sf{3tanx + 7 = 2sec^2x}$

We know that : sec²x = 1 + tan²x

$\implies \sf{3tanx + 7 =2(1 + tan^2x)}$

$\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}$

$\implies \sf{2tan^2x - 3 tanx - 5 = 0}$

$\implies \sf{2tan^2x - 5tanx + 2tanx - 5 = 0}$

$\implies \sf{2tanx(tanx + 1) - 5(tanx + 1) = 0}$

$\implies \sf{(tanx + 1)(2tanx - 5) = 0}$

$\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }$

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3 years ago

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vampirchik [111]

Answer:

-4

Step-by-step explanation:

PEMDAS

exponents -> 2^2 = 4

divide -> -36/4 = -9

add -> -9 + 5 = -4

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3 years ago

Evaluate: 3² × (-2)³ × 5​

Evaluate: 3² × (-2)³ × 5