Answer: The correct option is (B) less than 2.
Step-by-step explanation: Given that Y varies directly with X and has a constant rate of change of 6.
We are to find the possible value of X when the value of Y is 11.
Since Y varies directly with X, so we can write
![Y\propto X\\\\\Rightarrow Y=kx~~~~~~~~~~~~~~~(i),~~~~~~~~~\textup{[where 'k' is the constant of variation]}](https://tex.z-dn.net/?f=Y%5Cpropto%20X%5C%5C%5C%5C%5CRightarrow%20Y%3Dkx~~~~~~~~~~~~~~~%28i%29%2C~~~~~~~~~%5Ctextup%7B%5Bwhere%20%27k%27%20is%20the%20constant%20of%20variation%5D%7D)
Since the rate of change is constant and is equal to 6, so we must have

So, from equation (i), we have

Now, when Y = 11, then from equation (ii), we get

Thus, the value of X is less than 2 when Y = 11.
Option (B) is CORRECT.
Answer:
B
Step-by-step explanation:
If you graph y^2/361 + x^2/169=1 you will get the same graph depicted in the equation.
The actual rainfall for last June is 0.5
1.14 is the amount of rain that fell last July.
2.43 is how much rain would have to fall for August to match the three months average
0.86 is the departure from the average in August
Step-by-step explanation:
1. 0.67-0.17 = 0.5
2. 1.5-0.36 = 1.14
No it isn't. 5x is 5*x. not plus. so x would be 19 since 5*19=95