Answer: 8 or 2
Step-by-step explanation:
(x-5)^2=9
First square both sides to get rid of the power
(X-5)=3
Now add 5 to 3
X=8
Rearranging
(5-x)=3
Subtract 5 from 3=-2
-x=-2
so
X=2
A=-2 and b=5.
To have an infinite number of solutions, the two sides must be identical.
6x+15=-3(ax-b)
Using the distributive property,
6x+15=-3*ax--3*b
6x+15=-3ax+3b
This means -3ax=6x and 3b=15;
-3ax=6x
Divide both sides by -3:
-3ax/-3 = 6x/-3
ax=-2x
Divide both sides by x:
ax/x=-2x/x
a=-2
3b=15
Divide both sides by 3:
3b/3=15/3
b=5
C is non linear because if expanded It forms a parabola
Answer:
Step-by-step explanation:
The answer is B.
For A. its not true, the two triangles show that XW and RS are equivalent.
For C. its not true, the two triangles show that m<R is equal to m<X, not m<R=m<Y.
For D, its not true, the two triangles show that m<X is equal to m<R, not m<R=m<Y.
The two triangles show SSA, which prove that the triangle is equivalent. So, then, corresponding sides are considered equivalent. As a result, you can assume that ST=WY.
F(x)=(x-5)(x+6)/(x-3)
Check regions:
x=(-inf,-6) (-)(-)/(-)<0 -> f(x)<0, so NOT in solution set
x=-6, f(-6)=0 -> x=-6 in solution set <====================
x=(-6,3) (-)(+)/(-) >0 -> f(x) >0 so in solution set <==========
x=3 f(x) undefined, so NOT in solution set
x=(3,5) (-)(+)/(+) <0 so NOT in solution set
x=5 f(5)=0 -> x=5 in solution set <=====================
to sum up,
S={[-6,3),5}
