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marusya05 [52]
3 years ago
10

X + y =5 (x + 1)² +(y +1)² =25

Mathematics
1 answer:
algol [13]3 years ago
5 0
V nsdgggggubffbvwahdnx  fadsuo 
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A model plane is 1/48 the size of an actual plane. If the model plane is 28 inches long, how long is the actual plane?
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A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
7+(-3)+(-5)-10<br>how do i simplify ​
4vir4ik [10]

Answer:

-11

Step-by-step explanation:

7 - 3 - 5 - 10

4 - 5 - 10

- 1 - 10

-11

8 0
3 years ago
Help with math question please <br> thankksssss
Sedaia [141]
X equals 1 and 2. When you put 1 into f(x) you get 2 and when you put 1 into g(x) you get 1 as well. The same for 2...but not the same for 3.
7 0
3 years ago
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