The roots of the polynomial for this case will be x1 = 6, x2 = -6, x3 = 4, x4 = -4.You can solve the polynomial using the resolver after making the variable change u = x ^ 2 so that you have a second degree polynomial. Then return the change to find the missing roots. Attached solution.
Answer:
Step 1
Step-by-step explanation:
You distributed the 2 in 2(x-4) to get 2x-8
Multiply the number outside the parenthesis by each term inside the parenthesis:
2(v+5) = 2v + 10
Answer:
i cant see the link try reposting
Step-by-step explanation:
Yeah because he Sheldon do I be j I got work y’all got work at
