Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
Answer:
it is 4xy-4y^2+16x-16y
Step-by-step explanation:
My method is to "square them"
2x. -2y.
2y
8
2x * 2y
2x * 8
-2y*2y
-2y * 8
and add all the products together
20 comic books is the right awnser
Interest = 500 x .03 x 4
I = 60
Closing Balance = 500 (p) + 60 (1)
Closing Balance = 560
Answer:
b = 
Step-by-step explanation:
divide both sides by a
OR
bring the a over to the other side and put it under the c as the opposite of times is divide
