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3 years ago

What is the square root of -9 in simplest form

Mathematics

2 answers:

puteri [66]3 years ago

8 0

Answer:

Step-by-step explanation:

Square root -9

√(-9) = (3i)(3i)

Note that the "imaginary number" is a non-existent number. Note that in the rules of imaginary numbers: i * i = i² = -1

matrenka [14]3 years ago

4 0

It is 3i.
The square root of -9 is the square root of -1 times the square root of 9.
So: the square root of 9 is 3, and the square root of -1 is called i (this doesn't actually exist, it's just imaginary).
Then, the square root of -9 is 3i.

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For the geometric sequence of a1=2 and r=2 find a5

Brrunno [24]

Answer:

$a_5 = 32$

Step-by-step explanation:

The nth term for the geometric sequence is given by:

$a_n = a_1 \cdot r^{n-1}$

where,

$a_1$ is the first term

r is the common ratio

n is the number of terms.

As per the statement:

For the geometric sequence of $a_1=2$ and r=2

We have to find $a_5$

for n = 5;

$a_5=a_1 \cdot r^{n-1}$

Substitute the given values we have;

$a_5 = 2 \cdot 2^4 = 2 \cdot 16$

⇒ $a_5 = 32$

Therefore, the value of $a_5$ is, 32

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Step-by-step explanation:

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