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katen-ka-za [31]
3 years ago
8

PLEASE HELP!

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0
You have the function y= \dfrac{60x}{1+0.625x}. 
Rewrite it in the following way:

y= \dfrac{60x}{1+0.625x}=\dfrac{60x}{1+ \frac{5}{8} x}=\dfrac{480x}{8+5x}=\dfrac{96\cdot 5x}{8+5x}=
=\dfrac{96(5x+8-8)}{8+5x}=\dfrac{96(5x+8)}{8+5x}-\dfrac{96\cdot8}{8+5x}=96-\dfrac{768}{8+5x}.
This <span>function entry allows you to determine that y=96 is the horizontal asymptote and x=-8/5 is the vertical asymptote.
</span>
From the added graph of the function you can conclude that <span>the maximum number of moose that the forest can sustain at one time is 96.</span>
Answer: Correct choice is A.
<span />

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