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3 years ago

PLEASE HELP!

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

8 0

You have the function $y= \dfrac{60x}{1+0.625x}$ .
Rewrite it in the following way:

$y= \dfrac{60x}{1+0.625x}=\dfrac{60x}{1+ \frac{5}{8} x}=\dfrac{480x}{8+5x}=\dfrac{96\cdot 5x}{8+5x}=$
$=\dfrac{96(5x+8-8)}{8+5x}=\dfrac{96(5x+8)}{8+5x}-\dfrac{96\cdot8}{8+5x}=96-\dfrac{768}{8+5x}$ .
This function entry allows you to determine that y=96 is the horizontal asymptote and x=-8/5 is the vertical asymptote.

From the added graph of the function you can conclude that the maximum number of moose that the forest can sustain at one time is 96.
Answer: Correct choice is A.

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Answer:

Your answer of 10 x 12 - 14 +2+15 =123

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3 years ago

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3 years ago

Suppose 300 nursing students took a certification test that is worth 100 points.

Alja [10]

Answer:

225 students scored 65 or better and 75 students scored 88 or better.

Step-by-step explanation:

We are given that The five-number summary for the scores of 300 nursing students are given :

Minimum = 40

$Q_1 = 65$

Median = 82

$Q_3 = 88$

Maximum = 100

$Q_1$ is the first quartile and is the median of the lower half of the data set. 25% of the numbers in the data set lie below $Q_1$ and about 75% lie above $Q_1$ .

$Q_3$ is the third quartile and is the median of the upper half of the data set. 75% of the numbers in the data set lie below $Q_3$ and about 25% lie above $Q_3$

i) .About how many students scored 65 or better?

$Q_1 = 65$

Since we know that 75% lie above $Q_1$ .

So, Number of students scored 65 or better = $75\% \times 300 = \frac{75}{100} \times 300 =225$

ii)About how many students scored 88 or better?

$Q_3 = 88$

Since we know that 25% lie above $Q_3$

So, Number of students scored 88 or better = $25\% \times 300 = \frac{25}{100} \times 300 =75$

Hence 225 students scored 65 or better and 75 students scored 88 or better.

7 0

3 years ago