Answer:
896
Step-by-step explanation:
Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.
Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.
3 digit numbers with sum of 1:
The first and only number is 100 since 1+0+0=1.
We can't include 010 or 001 because these aren't really three digits long.
3 digit numbers with sum of 2:
The first number is 101 since 1+0+1=2.
The second number is 110 since 1+1+0=2.
The third number is 200 since 2+0+0=2.
That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.
So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.
This answer simplifies to 896.
The answer would be B) x = 4.
1.5x + 6 - 3 = 4.5x - 9
1.5x + 3 = 4.5x - 9
3 = 4.5x - 9 - 1.5x
3 = 3x - 9
3 + 9 = 3x
12 = 3x
12/3 = x
4 = x
x = 4.
Answer:
16
* usually means multiplication
If you have an open circle there instead, please inform me.
Step-by-step explanation:
* usually means multiplication
If you had an open circle there, please let me know.
Find h(10) and then multiply that answer to itself.
h(10)=6-10=-4
So the answer is -4*-4=16
Definition of additional: MORE, more, <em>and</em> more.
<em>Not </em>a definition of additional: SAME, same, and same.
We are given that EF is parallel to GH.
Remember, the definition of additional.
We wouldn't want the same piece of information, would we?
That's why we want a new piece of information:
Answer Choice B; FG parallel to EH.
Let the common multiple be x
3x : 2x
3x = 125
x = 125/3
So, B pays 2x = 2 × 125/3 = £250/3
