Question

20 PTS!!! Math pls help

Answer 1

Answer:

The answer to your question is: 30 u²

Step-by-step explanation:

Process

1.- Calculate the length of the base and the length of the height

dAB = $\sqrt{(x2-x1)^{2} + (y2 - y1)^{2} }$

dAB = $\sqrt{(5+ 3)^{2} + (1 - 5)^{2} }$

dAB = $\sqrt{8^{2} + (-4)^{2} }$

dAB = $\sqrt{64 + 16}$

dAB = $\sqrt{80}$

dCD = $\sqrt{(x2-x1)^{2} + (y2 - y1)^{2} }$

dCD = $\sqrt{(-4 + 1)^{2} + (-2 - 4)^{2} }$

dCD = $\sqrt{(-3)^{2} + (-6)^{2} }$

dCD = $\sqrt{9 + 36}$

dCD = $\sqrt{45}$

Area of a triangle    = base x height / 2

                                 = $\frac{\sqrt{80} \sqrt{45} }{2}$

                                 $= \frac{\sqrt{3600} }{2}$

                                 $= \frac{60}{2}$

                                         = 30 u²