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3 years ago

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A city had 5.4 inches of rain in September and 4.5 inches of rain in October. What is the difference in rainfall between the two

months?

2 answers:

kvasek [131]3 years ago

8 0

You subtract 5.4 to 4.5
The answer is 0.9

cupoosta [38]3 years ago

4 0

.9 inches just subtract the 2 numbers <span />

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A radio station broadcasts a signal over qn area with a radius of 50 miles. The station can relay the signal and broadcast over

denpristay [2]

A = pi * r^2
<span>A = 3.14 * 50^2 </span>
<span>A = 7,850 square miles (area of the 50 mile broadcast signal)

A = pi * r^2
A = 3.14 * 75^2
A = </span>17,662.5 = 17,663 square miles (area of the 75 mile relayed signal)

Now we just need to subtract the 50 mile signal from the 75 mile signal, so:

17,663 - 7,850 = <span>9,813 square miles greater

Hope this helps :)
</span>

7 0

3 years ago

What is the approximate perimeter?

vladimir1956 [14]

300^2 + 500^2 = c^2
9000 + 250000=c^2
340000=c^2
sqrt (340000) = c
c = 583
300 + 500 + 583 = 1383
1380 is the perimeter

8 0

2 years ago

What is the midpoint of (-23,-14) and (-18,2)

zloy xaker [14]

Given two coordinates point 1 as (-23,-14) and point 2 as(-18,2).

To find the midpoint we would use the formula below;

$\text{midpoint(x,y)}=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})$

Where x1=-23, x2=-18, y1=-14, y2=2

We would substitute the values into the midpoint formula.

$\begin{gathered} \text{midpoint =(}\frac{-23-18}{2},\frac{-14+2}{2}) \\ =(-\frac{41}{2},-6) \end{gathered}$

Therefore, the answer is

$\text{midpoint}=(-\frac{41}{2},-6)$

7 0

1 year ago

Does anyone under stand this one ??

Annette [7]

Answer:

its c i belive'

Step-by-step explanation:

5 0

2 years ago

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Carrie and brent leave home at the same time. carrie drives due east at a rate of 30 mph, while brent drives due south at a rate

Helga [31]

<h3>They are 268 miles far apart after 4 hours</h3>

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<u>Given :</u>

v₁ = 30 mph due east

v₂ = 60 mph due south

t = 4 hours

<u>Unknown :</u>

displacement = d = ?

<u>Solution :</u>

$d_1 = v_1 \times t$

$d_1 = 30 ~ mph \times 4 ~ h$

$d_1 = \boxed {120 ~ miles}$

$d_2 = v_2 \times t$

$d_2 = 60 ~ mph \times 4 ~ h$

$d_2 = \boxed {240 ~ miles}$

$d^2 = (d_1)^2 + (d_2)^2$

$d^2 = 120^2 + 240^2$

$d^2 = 72000$

$d = \sqrt{72000}$

$d = 120\sqrt{5} ~ miles$

$d \approx \boxed {268 ~ miles}$

<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

6 0

3 years ago

Read 2 more answers