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Mice21 [21]
3 years ago
12

If A and B are mutually exclusive then: (A) P(A/B) = 0 (B) P(A/B) =P(B) (C) P(A or B) = 0 (D) P(A/B) = P(A) (E) none of the abov

e
Mathematics
1 answer:
Elis [28]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Two events are termed to be mutually exclusive if they cannot happen at the same time. This means that the probability of occurring at the same time is zero.

A is correct.

The probability of the two events happening at the same time is zero

B is incorrect

The probability of both happening at the same is not equal to the probability of B alone

C is incorrect

The probability of the union of the two is never equal to zero since they might occur at different times

D. Is incorrect

The probability of both happening at the same time is never equal to the probability of A alone

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A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a s
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Answer:

88.51 is the minimum score needed to receive a grade of A.          

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73

Standard Deviation, σ = 11

We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.0793.

P( X \geq x) = P( z \geq \displaystyle\frac{x - 73}{11})=0.0793  

= 1 -P( z \leq \displaystyle\frac{x - 73}{11})=0.0793  

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P(z \leq 1.410) = 0.9207

\displaystyle\frac{x - 73}{11} = 1.410\\x =88.51  

Hence, 88.51 is the minimum score needed to receive a grade of A.

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