<span>B. (1, –3)
</span><span>x – y = 4
8x + 2y = 2
1 - (-3) = 4
8(1) + 2(-3) =
8 - 6 = 2
True
hope this helps</span>
Answer:
88.51 is the minimum score needed to receive a grade of A.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73
Standard Deviation, σ = 11
We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.0793.
Calculation the value from standard normal z table, we have,

Hence, 88.51 is the minimum score needed to receive a grade of A.
D. N/88=16
quotient means divisions so the quotient of a number and 88 is n/88.
Hey, you didn’t add the options or following expressions. Can you add them in the comments so I can try and help you out?