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iren2701 [21]
3 years ago
13

What is the solution of the inequality (x-4)(x+3) more then or equal to zero? Graph Solution.

Mathematics
1 answer:
AnnZ [28]3 years ago
7 0

ANSWER

x \leqslant  - 3,x \geqslant 4

EXPLANATION

The given inequality is

(x - 4)(x  + 3) \geqslant 0

To solve this inequality, we need to solve the corresponding equation:

(x - 4)(x  + 3) =  0

This implies that

x =  - 3 \: or \: x = 4

We now plot the solutions of the equation and use it to solve the corresponding inequality as shown in the attachment.

These values divide the number line into 3 regions.

The region(s) that satisfies the inequality is the solution set

From the graph the solution is

x \leqslant  - 3,x \geqslant 4

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Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

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The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

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Now we can calculate the charges,

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Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

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3 years ago
An office and apartment building is made up of modules. Each module is a rectangular prism. The building has 150 modules, and is
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Answer:

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Step-by-step explanation:

Part 1)

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Answer:

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Step-by-step explanation:

i hope this will help you

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Answer:

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Step-by-step explanation:

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