In this challenge, write a function to add two floating point numbers. Determine the integer floor of the sum. The floor is the
1 answer:
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Answer:
Here is the JAVA program:
import java.util.Scanner; //to take input from user
public class Main{
public static void main(String[] args) { //start of main function
Scanner input = new Scanner(System.in); // creates Scanner class object
int num, integer, odd = 0, even = 0; //declare variables
System.out.print("Enter the number of integers: "); //prompts user to enter number of integers
num = input.nextInt(); //reads value of num from user
System.out.print("Enter the integers:\n"); //prompts user to enter the integers
for (int i = 0; i < num; i++) { //iterates through each input integer
integer = input.nextInt(); // reads each integer value
if (integer % 2 == 0) //if integer value is completely divisible by 2
even += integer; //adds even integers
else //if integer value is not completely divisible by 2
odd += integer; } //adds odd integers
System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers
System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers
}}
Explanation:
The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.
Suppose user wants to input 5 integers. So,
num = 5
Suppose the input integers are:
1, 2 , 3, 4, 5
for (int i = 0; i < num; i++) is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.
At first iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 1
if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:
odd += integer; this becomes:
odd = odd + integer
odd = 1
Now the value of i is incremented to 1 so i=1
At second iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 2
if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So
even += integer; this becomes:
even= even+ integer
even = 2
Now the value of i is incremented to 1 so i=2
At third iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 3
if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So
odd += integer; this becomes:
odd= odd + integer
odd= 1 + 3
odd = 4
Now the value of i is incremented to 1 so i=3
At fourth iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 4
if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So
even+= integer; this becomes:
even = even + integer
even = 2 + 4
even = 6
Now the value of i is incremented to 1 so i=4
At fifth iteration:
integer = input.nextInt(); statement reads the value of input integer. The first integer is 5
if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So
odd+= integer; this becomes:
odd= odd+ integer
odd= 4 + 5
odd = 9
Now the value of i is incremented to 1 so i=5
When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So
even = 6
odd = 9
Hence the output is:
Sum of Even Numbers: 6 Sum of Odd Numbers: 9
Answer:
I am writing the program in JAVA and C++
JAVA:
public int createLicenseNum(int customID){ //class that takes the customID as parameter and creates and returns the licenseNum
licenseNum = (100000 * customID) + licenseYear; //licenseNum creation formula
return(licenseNum); }
In C++ :
void DogLicense::CreateLicenseNum(int customID){ //class that takes the customID as parameter and creates the licenseNum
licenseNum = (100000 * customID) + licenseYear; } //licenseNum creation formula
Explanation:
createLicenseNum method takes customID as its parameter. The formula inside the function is:
licenseNum = (100000 * customID) + licenseYear;
This multiplies 100000 to the customID and adds the result to the licenseYear and assigns the result of this whole expression to licenseNum.
For example if the SetYear(2014) means the value of licenseYear is set to 2014 and CreateLicenseNum(777) this statement calls createLicenseNum method by passing 777 value as customID to this function. So this means licenseYear = 2014 and customID = 777
When the CreateLicenseNum function is invoked it computes and returns the value of licenseNum as:
licenseNum = (100000 * customID) + licenseYear;
= (100000 * 777) + 2014
= 77700000 + 2014
licenseNum = 77702014
So the output is:
Dog license: 77702014
To call this function in JAVA:
public class CallDogLicense {
public static void main(String[] args) {//start of main() function
DogLicense dog1 = new DogLicense();//create instance of Dog class
dog1.setYear(2014); // calls setYear passing 2014
dog1.createLicenseNum(777);// calls createLicenseNum passing 777 as customID value
System.out.println("Dog license: " + dog1.getLicenseNum()); //calls getLicenseNum to get the computed licenceNum value
return; } }
Both the programs along with the output are attached as a screenshot.
