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Nat2105 [25]
3 years ago
14

How do you recognize substances that have gone through physical or chemical changes?

Computers and Technology
2 answers:
Leviafan [203]3 years ago
7 0
Normally  you can't.   You cannot tell if water has been frozen and then thawed.
Valentin [98]3 years ago
5 0

Answer:

you normally cant tell if something went through chemical change, like sugar and coffee, after the sugar melts into the coffee you cant get it back or tell if there is sugar in it by looking at it.

Explanation:

hope this helps! :)

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. Which of the following is NOT a
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Answer:

solution

Explanation:

The correct option is - solution

Reason -

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4 years ago
1. INTRODUCTION In this project, you will gain experience with many of the Python elements you’ve learned so far, including func
yulyashka [42]

Answer:

See Explaination

Explanation:

def process_string(s):

global char#global varibles

char=[]

global count

count=[]

for i in s:

#checking whether i is alphabet or not

if(i.isalpha()):

#converting to lower

i=i.lower()

if i in char:

#if char already present increment count

count[char.index(i)]+=1

else:

#if char not present append it to list

char.append(i)

count.append(1)

#menu

print("1. Enter a string")

print("2. Display the string")

print("3. Reverse the string")

print("4. Append a string to the existing one")

print("5. Slice the string")

print("6. Display the number of occurences of each letter")

print("7. Quit")

op=input("Enter option:")

#as I don't know what you have covered

#I am trying to make it simple

#checking whether input is numeric or not

#you can use try except if you want

while(not op.isnumeric()):

op=input("Enter valid option:")

op=int(op)

global x

while(op!=7):

if(op==1):

x=input("Enter a string: ")

elif(op==2):

print("The string is:",x)

elif(op==3):

x=x[::-1]#reversing the string

print("The string is:",x)

elif(op==4):

y=input("Enter a string: ")

x=x+y #string concatnation

elif(op==5):

a=input("Enter first integer: ")

while(not a.isnumeric()):

a=input("Enter valid first integer: ")

a=int(a)

b=input("Enter second integer: ")

while(not b.isnumeric()):

b=input("Enter valid second integer: ")

b=int(b)

x=x[a:b]#string slicing

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elif(op==6):

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for i in range(len(char)):

print(char[i],",",count[i])

else:

#incase of invalid input

print("Invalid option")

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print("3. Reverse the string")

print("4. Append a string to the existing one")

print("5. Slice the string")

print("6. Display the number of occurences of each letter")

print("7. Quit")

op=input("Enter option:")

while(not op.isnumeric()):

op=input("Enter valid option:")

op=int(op)

6 0
3 years ago
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