Answer:
A yes
B no
C yes
D yes
Step-by-step explanation:
sorry I don't know how to do the other one
The answer is 15.
Using the distance formula you’d get. Sqrt(-2-7)^2+(-10-2)^2
Sqrt(-9)^2+(-12)^2
Sqrt(81+144)
Sqrt(225)
D=15
Answer:
a) 0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.
b) 0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.
Step-by-step explanation:
Question a:
20% of employees engage in physical exercise.
This 20% is composed by:
8% of 60%(males)
x% of 100 - 60 = 40%(females).
Then, x is given by:




0.38 = 38%
Probability of being a female who engages in exercise:
40% are female, 38% of 40% engage in exercise. So
0.38*0.4 = 0.152
0.152 = 15.2% probability that this person is a female who engages in physical exercise activities during the lunch hour.
B. If we choose an employee at random from this corporation,what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour?
40% are female, 100% - 38% = 62% of 40% do not engage in exercise. So
0.62*0.4 = 0.248
0.248 = 24.8% probability that this person is a female who does not engage in physical exercise activities during the lunch hour.
Answer:
i may be wroung but it should be 90
Step-by-step explanation:
3.25(4)+2(6) --plug in values
13+12 --multiply
$25 --answer