Answer:
1/3 of black F2 progeny will be homozygous.
Explanation:
Here, BB = black coat color = true breeding dominant black strain
bb = white coat color = true breeding recessive white strain
When true breeding black and white guinea pigs are mated to give F1 progeny:
BB X bb = Bb ( all black guinea pigs )
When two of the F1 guinea pigs are mated to give F2 progeny:
Bb X Bb = BB, Bb, Bb, bb
F2 progeny has 3/4 progeny as black (BB and Bb) . Out of them 1/3 are homozygous and 2/3 are heterozygous.
Hence, 1/3 of black F2 progeny will be homozygous.
Seldom seen in adults treatment with insulin injections
Answer:
"...for many of our white brothers, as evidenced by their presence here today, have come to realize that their destiny is tied up with our destiny."
(A)
The answer to your question is B- introduction of non-native animal species
So if it's 20% adenine (A) then it's 20% (T)...because A always pairs with T. That adds up to 40%....60% therefore is G+C...so you'd have 30% Cytosine (C) and 30% Guanine (G).
