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3 years ago

Solve. Check for extraneous solutions. (x-2)^(1/2) - (28 - 2x)^(1/4) = 0

Mathematics

1 answer:

Bingel [31]3 years ago

3 0

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3 years ago

Math questionnnnn thanks if you helop

kipiarov [429]

Answer:

Step-by-step explanation:

Replace X with 2

Evaluate the function. g(x) = 3x^2 – 2x + 5 Find f(2)

g(x) = 3(2)^2 – 2(2) + 5

Next conduct PEMDAS

Exponents are first so solve 2^2 which is 2 x 2 = 4

g(x) = 3(4) – 2(2) + 5

Next step is multiplication multiply 3 x 4 and 2x2

g(x) = 12 – 4 + 5

conduct adding and subtracting left from right

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2 years ago

Complete the square x^2+45=-14x

Rom4ik [11]

2
+
4
5
=
−
1
4

x
2
+
45
=
−
14
x
x2+45=−14x

2
+
4
5
−
−
1
4

=
0

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2 years ago

3. A line goes through the points (3,4) and (-3,6).

Galina-37 [17]

Answer:

Part a) The slope is $m=-\frac{1}{3}$

Part b) The equation in point slope form is $y-4=-\frac{1}{3}(x-3)$

Part c) The equation in slope-intercept form is $y=-\frac{1}{3}x+5$

Step-by-step explanation:

we have the points (3,4) and (-3,6)

Part a) What is the slope of the line?

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given points

$m=\frac{6-4}{-3-3}$

$m=\frac{2}{-6}$

$m=-\frac{1}{3}$

Part b) Write the equation of the line in point-slope form

$y-y1=m(x-x1)$

we have

$m=-\frac{1}{3}$

$point\ (3,4)$

substitute

$y-4=-\frac{1}{3}(x-3)$ ---> equation in point slope form

Part c) Write the equation of the line in slope-intercept form

$y=mx+b$

we have

$y-4=-\frac{1}{3}(x-3)$

Isolate the variable y

distribute right side

$y-4=-\frac{1}{3}x+1$

Adds 4 both sides

$y=-\frac{1}{3}x+1+4$

$y=-\frac{1}{3}x+5$ ---> equation in slope intercept form

7 0

2 years ago