Answer:
The probability is 0.9211
Step-by-step explanation:
Let's call K the event that the student know the answer, G the event that the student guess the answer and C the event that the answer is correct.
So, the probability P(K/C) that a student knows the answer to a question, given that she answered it correctly is:
P(K/C)=P(K∩C)/P(C)
Where P(C) = P(K∩C) + P(G∩C)
Then, the probability P(K∩C) that the student know the answer and it is correct is:
P(K∩C) = 0.7
On the other hand, the probability P(G∩C) that the student guess the answer and it is correct is:
P(G∩C) = 0.3*0.2 = 0.06
Because, 0.3 is the probability that the student guess the answer and 0.2 is the probability that the answer is correct given that the student guess the answer.
Therefore, The probability P(C) that the answer is correct is:
P(C) = 0.7 + 0.06 = 0.76
Finally, P(K/C) is:
P(K/C) = 0.7/0.76 = 0.9211
It is 46 if you divide 34 by 16 you get 2.125 then divide 100 by 2.125 and you get 47.05 the 0 means go down if you are rounding which brings it to 46
Answer:
Here, 
denotes number of frosting flowers
Step-by-step explanation:
Let denotes number of frosting flowers.
Amount charged by baker for each batch of cupcakes = $30
Amount charged for each frosting flower = $0.09
So,
Amount charged for frosting flowers = 
Therefore,
Total cost of a batch of cupcakes with frosting flowers =
1. Two of the main identities used in trigonometry for right triangles (Triangles that have an angle of 90°) are: Sine (Sin) and Cosine (Cos).
Sin x°=Opposite/Hypotenuse
Cos x°=Adjacent/Hypotenuse
2. The inverse of Sinx° is Cosec x°, then:
Cosec x°=1/Sin x°
3. The inverse of Cos x° is Sec x°, then:
Sec x°=1/Cos x°
4. Keeping this on mind, you have:
Cosc x°=Hypotenuse/Opposite
Sec x°=Hypotenuse/Adjacent
5. Therefore, the correct answer is:
The third option: Cosec x°=Hypotenuse/Opposite.
Answer:
The 3rd option is correct.
Step-by-step explanation:
This is because of an exponent rule that goes:
(xy)^z = x^z(y^z)
The whole thing gets raised to the power. Therefore only the 3rd one works (ps. if you can mark as brainliest that would be amazing, but if not that's fine)
