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Nonamiya [84]
3 years ago
15

On a coordinate plane, a line goes through (negative 5, negative 4) and (0, negative 3). A point is at (negative 2, 2). What is

the equation of the line that is parallel to the given line and passes through the point (–2, 2)? y = One-fifthx + 4 y = One-fifthx + Twelve-fifths y = –5x + 4 y = –5x + Twelve-fifths
Mathematics
2 answers:
Assoli18 [71]3 years ago
8 0

Answer:

(B) y=1/5x +12/5

Step-by-step explanation:

Sav [38]3 years ago
4 0

Answer:

Second option: y=\frac{1}{5}x+\frac{12}{5}

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

We know that a line goes through the points (-5,-4) and (0,-3)

Since the line intersects the y-axis when x=0, then the y-intercept of this line is:

b=-3

Substitute the y-intercept and coordinates of the point  (-5,-4) into the equation y=mx+b and solve for "m":

-4=m(-5)-3\\\\-4+3=-5m\\\\m=\frac{-1}{-5}\\\\m=\frac{1}{5}

By definition, the slopes of parallel lines are equal, then the slope of the other line is:

m=\frac{1}{5}

Knowing that it passes through the point (-2, 2), we can substitute values into the equation  y=mx+b and solve for "b":

 2=\frac{1}{5}(-2)+b\\\\2+\frac{2}{5}=b\\\\b=\frac{12}{5}

Therefoe, the equation of this line is:

 y=\frac{1}{5}x+\frac{12}{5}

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