4. How much sand would you need to fill this box? *<br><br> 3 ft<br> 2 ft<br> 5 ft

Six more than 1/5 a number is 12. What is the number

suter [353]

Answer:

Step-by-step explanation:

let x be the number

6+1/5x=12

1/5x=12-6

1/5x=6

x=5*6

x=30

check: 6+(1/5*30)=6+6=12

8 0

2 years ago

Please help on two math questions. I don’t understand how to do them.

Sidana [21]

When you represent intervals on the number line, you're including full dots, excluding empty dots, and you're considering numbers highlighted by the line.

In the first case, you've highlighted everything before -2 (full dot, thus included), and everything after 1 (empty dot, excluded). So, the set would be

$x\leq -2 \lor\ x>1$

or, in interval notation,

$(-\infty,-2]\cup (1,\infty)$

In the second case, you are looking for all numbers between -3 and 5. This interval is symmetric with respect to 1: you're considering all numbers that are at most 4 units away from 1, both to the left and to the right.

This means that the difference between your numbers at 1 must be at most 4, which is modelled by

$|x-1|\leq 4$

where the absolute values guarantees that you'll pick numbers to the left and to the right of 1.

3 0

2 years ago

If 2(x + 3) = x + 10, then x equals what

Rama09 [41]

Answer:

$x=4$

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You need to apply the Distributive property on the left member of the equation:

$2(x + 3) = x + 10\\ 2x+6=x+10$

2. Now, you must solve for $x$ , as following:

$2x-x=10-6\\ x=4$

8 0

3 years ago

John is selling tickets to an event. Attendees can either buy a general admission ticket, x,

Masteriza [31]

John sold 18 general admission tickets and 11 VIP tickets.

Step-by-step explanation:

Given,

Cost of each general admission = $50

Cost of each VIP ticket = $55

Total tickets sold = 29

Total revenue generated = $1505

Let,

x represent the number of general admission tickets sold

y represent the number of VIP tickets.

x+y=29 Eqn 1

50x+55y=1505 Eqn 2

Multiplying Eqn 1 by 50

$50(x+y=29)\\50x+50y=1450\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(50x+55y)-(50x+50y)=1505-1450\\50x+55y-50x-50y=55\\5y=55$

Dividing both sides by 5

$\frac{5y}{5}=\frac{55}{5}\\y=11$

Putting y=11 in Eqn 1

$x+11=29\\x=19-11\\x=18$

John sold 18 general admission tickets and 11 VIP tickets.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

5 0

3 years ago

What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?

DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. $\frac{n(n-3)}{2}$

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

$\frac{n(n-3)}{2}$

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = $\frac{6(6-3)}{2}$

= $\frac{18}{2}$

= 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = $\frac{7(7-3)}{2}$

= $\frac{28}{2}$

= 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = $\frac{30(30-3)}{2}$

= $\frac{810}{2}$

= 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = $\frac{n(n-3)}{2}$

The number of diagonals in a n-gon is $\frac{n(n-3)}{2}$

7 0

2 years ago

4. How much sand would you need to fill this box? * 3 ft 2 ft 5 ft