Answer:
x = 25
Step-by-step explanation:
It is given that,
JK =5x+17,
KL = x -1,
JL=7x-9
We need to find the range of possible values for x.
It can be assumed that K is a mid point of JL.
JL = JK + KL
Putting all the values,
7x-9 = 5x+17 + x -1
Taking like terms together,
7x-5x-x = 17-1+9
x = 25
So, the value of x is 25.
Answer:
57 units
Step-by-step explanation:
So the step is we need to find out the scale factor
And the scale factor is 24/8 =3
So the parameter of ANG is
19×3
=57
1. X + 5
2.15-15
3. C= ( 3x9.95)+(2x14.98)
4.?
5. 12,000+500x ?idk
Well here are two equivalent different expressions of my making that you could use for this question.
f(x) = 2x - 7
g(x) = 3x - 28 / 2
When x = 7, these two different expressions will equate to the same value of 7. If you meant something else let me know, otherwise this is what you should put for your essay-question.
