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Doss [256]
4 years ago
12

What number raise to the -2 exponet would equal 1/4 ​

Mathematics
1 answer:
Svetradugi [14.3K]4 years ago
6 0
So x^2 = 1/4. Take square root of each side
You might be interested in
What is the image point of (5,0)(5,0) after a translation left 2 units and down 4 units?
Kamila [148]

(5,0)

translation

left 2 units: 5 -2 = 3

down 4 units: 0 - 4 = -4


Image point (3 , -4)

7 0
4 years ago
I have 18ones,15hundreds,15tens,and 8 thousands
Oksanka [162]

9668

Explanation:

18 ones, 18x1=18

15 hundreds, 15x100 =1500

15 tens, 15x10=150

8 thousands,8x1000=8000

8x1000=800018+1500+150+8000=9668

<em>Hope</em><em> this</em><em> answer</em><em> correct</em><em> </em><em>:</em><em>)</em>

5 0
3 years ago
Everyone wants to watch football games on Thanksgiving. There are 3 games on in afternoon and 3 on at night. How many different
Vikki [24]

Answer:

Step-by-step explanation:

At afternoon there are 3 games, lets call them A1, A2, and A3. These are simultaneous, which means you can ONLY watch one of them.

At night there are other three, lets call them N1, N2 and N3. Which again, are simultaneous, so you need to chose only one.

So, you can, at most, watch 2 games: one in the afternoon (extracted from the set {A1, A2, A3}) and one at night (extracted from the set {N1, N2, N3}).

So, here what you need is ALL the possible combinations between afternoon and games. As thee choices are independent, this is, the game chosen at afternoon has no effect on the night decision, we can just multiply the number of options in every set: 3*3 = 9. So there are 9 different combinations, which are:

A1 N1, A1 N2, A1 N3, A2 N1, A2 N2, A2 N3, A3 N1, A3 N2, A3 N3.

Here I supposed you watch a game in both, night and afternoon. If you can choose to NOT watch any game, the sets will have 4 elements but the reasoning is equal.  

7 0
3 years ago
set up and solve a system of equations to solve the problem The school band sells carnations on Valentine's Day for $3 each. It
sasho [114]

Answer:

Number of carnations = 6

Step-by-step explanation:

Let the number of carnations school band buys from florist be x.

Cost of each carnation = $0.50

Total cost for x number of carnations = $0.50x

Also , delivery cost = $15

So, total cost on buying x number of carnations from florist = 0.50x + 15

Now,

School band sells carnations at a price of $3 each.

Total revenue they get get after selling x number of carnations = $3x

We need to find that , when will the cost of the carnations be equal to the revenue from selling them.

i.e 3x = 0.50x + 15

or 3x - 0.50x = 15

or 2.50x = 15

or x = \frac{15}{2.50}

or x = 6

so on selling 6 carnations cost of carnation reach to the point where it is equal to revenue  


4 0
3 years ago
5. Suppose you are the manager of a music store. At the end of one week you are going over
Vaselesa [24]

Answer:

Step-by-step explanation:

x = cheaper compact disc

y = more expensive compact disc

x + y = 375.....x = 375 - y

12.95x + 14.95y = 5306.25

12.95(375 - y) + 14.95y = 5306.25

4856.25 - 12.95y + 14.95y = 5306.25

4856.25 + 2y = 5306.25

2y = 5306.25 - 4856.25

2y = 450

y = 450/2

y = 225 <==== there were 225 of the more expensive compact discs sold

x + y = 375

x + 225 = 375

x = 375 - 225

x = 150 <==== there were 150 of the cheaper compact discs sold

check...

12.95x + 14.95y = 5306.25

12.95(150) + 14.95(225) = 5306.25

1942.50 + 3363.75 = 5306.25

5306.25 = 5306.25 (correct)

8 0
3 years ago
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