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ch4aika [34]
3 years ago
9

10% off the original price the original price is $52 what is the sale price

Mathematics
1 answer:
lbvjy [14]3 years ago
5 0
$520. I think it is since 52 is 10% of 520. Hope this helps
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Please answer this ??
Vadim26 [7]
The answer is 24.5. Just plug the numbers in
7 0
2 years ago
The Weight On Earth Compared To Some Rando Planet... pls help
earnstyle [38]

Answer:

if your talking about the earth i dont know because no one have ever compared some random planet and earths weight

Step-by-step explanation:

That’s because the planets weigh different amounts, and therefore the force of gravity is different from planet to planet. For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That’s because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.

3 0
2 years ago
A carpet layer can put down 400 square feet of carpet in 2.5 hours. How many hours will it take to lay down 600 square feet of c
Tresset [83]
First take 400 and divide it by 2.5 to find the hourly rate. Then divide 600 by the hourly rate (160) to get 3.75 hours. My work is listed below.

5 0
3 years ago
If the 50th and 51st terms of an arithmetic sequence are 140 and 142, find the 1st term
morpeh [17]

Answer:

The first term is 42.

Step-by-step explanation:

The common difference is 142  - 140 = 2 so we have

50th term = a1 + 2(50 -1) = 140    where a1 is the first term

a1 + 98 = 140

a1 = 140 - 98 =  42.

4 0
3 years ago
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
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