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jeyben [28]
3 years ago
6

16 is 40% of what number?

Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0
\begin{array}{cccc}16&-&40\%&|divide\ both\ sides\ by\ 4\\4&-&10\%&|multiply\ both\ sides\ by\ 10\\40&-&100\%\end{array}\\\\Answer:\boxed{16\ is\ 40\%\ of\ 40}
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4 divided by the sum of x and 1 equals the quotient of 3 and the difference of x and 1
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x=7

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John earns $6.50 per hour. he worked 40.0 hours last week. what was the amount of his check?
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John gains 6.50 an hour
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Step-by-step explanation:

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According to a Pew Research Center, in May 2011, 35% of all American adults had a smart phone (one which the user can use to rea
Veronika [31]

Answer:

p_v =P(z>1.82)=0.034  

Assuming a standard significance level of \alpha=0.05 the best conclusion for this case would be:

4. There is not enough evidence to show that more than 35% of community college students own a smart phone (P-value = 0.034).

Because p_v

If we select a significance level lower than 0.034 then the conclusion would change.

Step-by-step explanation:

Data given

n=300 represent the random sample taken

X=120 represent the people who have a smart phone

\hat p=\frac{120}{300}=0.4 estimated proportion of people who have a smart phone

p_o=0.35 is the value that we want to test

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to test the claim that the true proportion of people who have a smart phone is higher than 0.35, the system of hypothesis are.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.35}{\sqrt{\frac{0.35(1-0.35)}{300}}}=1.82  

Statistical decision  

Since is a right tailed test the p value would be:  

p_v =P(z>1.82)=0.034  

Assuming a standard significance level of \alpha=0.05 the best conclusion for this case would be:

4. There is not enough evidence to show that more than 35% of community college students own a smart phone (P-value = 0.034).

Because p_v

If we select a significance level lower than 0.034 then the conclusion would change.

4 0
3 years ago
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