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igomit [66]
3 years ago
13

PLZ HELP IT IS URGENT 55 POINTS MOST BRAINLIEST

Mathematics
1 answer:
amm18123 years ago
3 0

This is physics not math.  Presumably that's square meters.  

pressure = force / area

p = 1 / (.0600) = 16.7 Newtons per square meter

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What is the 37th term of the arithmetic sequence with the first term -39 and the common difference of 8.
Mrrafil [7]

Answer:

a_{37}=249

Step-by-step explanation:

A sequence that has a common difference is an <em>arithmetic sequence</em>:

a_n=a_1+(n-1)d

where aₙ is the nth term, n is the index, and d is the common difference.

In your question:

  • n = 37
  • a₁ = -39
  • d = 8

Plug those into the formula:

a_{37}=-39+(37-1)8

Then solve:

a_{37}=-39+(36)8\\a_{37}=-39+288\\a_{37}=249

8 0
3 years ago
Simplify -51/4-(-71/2). Which of the following is correct
DENIUS [597]

Answer:

Step-by-step explanation:

22.75

4 0
3 years ago
Read 2 more answers
One week, a cake shop sold 45 pineapple cakes and 62 chocolate cakes on the weekdays and 55 pineapple cakes and 79 chocolate cak
lora16 [44]

Answer:

Let us assume cost of each pineapple cake = $x.


Cost of each chocolate cakes = $y.


On weekdays 45 pineapple cakes and 62 chocolate cakes were sold.


Total cost of 45 pineapple cakes and 62 chocolate cakes were sold =  $3,520.


Therefore, first equation would be


45x + 62y = 3520  --------------equation(1).


On weekends 55 pineapple cakes and 79 chocolate cakes were sold.


Total cost of 55 pineapple cakes and 79 chocolate cakes were sold =  $4,415.


Therefore, second equation would be


55x + 79y = 4415   --------------equation(2).


Therefore, system of equation are 45x + 62y = 3520  and 55x + 79y = 4415.

And we can form a matrix as

.

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the larg
katovenus [111]
Problema Solution

You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the largest dimensions of this enclosure that you could build?

Answer provided by our tutors

Make a drawing and denote:


x = half of the length of the enclosure


2x = the length of the enclosure


y = the width of the enclosure


P = 800 ft the perimeter


The perimeter of the two enclosures can be expressed P = 4x + 2y thus


4x + 3y = 800


Solving for y:

........

click here to see all the equation solution steps

........

y = 800/3 - 4x/3


The area of the two enclosure is A = 2xy.


Substituting y = 800/3 - 4x/3 in A = 2xy we get


A = 2x(800/3 - 4x/3)


A =1600x/3 - 8x^2/3


We need to find the x for which the parabolic function A = (- 8/3)x^2 + (1600/3)x has maximum: 


x max = -b/2a, a = (-8/3), b = 1600/3


x max = (-1600/3)/(2*(-8/3))


x max = 100 ft


y = 800/3 - 4*100/3


y = 133.33 ft


2x = 2*100


2x = 200 ft

3 0
3 years ago
Ayuda por favor necesito esto para terminar los modulos​
fredd [130]
La respuesta sería A
8 0
3 years ago
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