Question

Find the term independent of x in the expansion of

Answer 1

Step-by-step explanation:

$\frac{19683x {}^{18} }{512} - \frac{59049x {}^{15} }{512} + \frac{19683x {}^{12} }{128 } - \frac{15309x {}^{9} }{?128} + \frac{15309x {}^{6} }{256} - \frac{15309x {}^{9} }{128} + \frac{15309x {}^{6} }{?256} - \frac{5103x {}^{3} }{256} + \frac{567}{128} - \frac{81}{128x {}^{3} } + \frac{27}{512x {}^{6} } - \frac{1}{512x {}^{9} }$ it's long there's some calculations in de side hope its helpful