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djyliett [7]
3 years ago
8

When you multiply two complex numbers in polar form, what happens to the angles?

Mathematics
1 answer:
prisoha [69]3 years ago
6 0

The angles get added.

Let <em>z</em> = <em>r</em> exp(<em>i</em> <em>θ</em>) and <em>w</em> = <em>s</em> exp(<em>i</em> <em>φ</em>). Then

<em>zw</em> = <em>rs</em> exp(<em>i</em> <em>θ</em>) exp(<em>i</em> <em>φ</em>) = <em>rs</em> exp(<em>i</em> (<em>θ</em> + <em>φ</em>))

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Solve the equation for the indicated variable.<br>1. y= 3/8 (x+4) for x​
madam [21]

Answer:

x=8y/3-4

Step-by-step explanation:

What we have to do to solve for X into re arrange the equation so that X is by itself on one side of the equation.  To start we will divide both sides by 3/8 to move it away from the X side and we get

8y/3=x+4 then we will subtract both sides by 4 to get x all by itself

8y/3-4=x

I hope this helps and please don't hesitate to ask if there is anything still unclear!

6 0
3 years ago
Read 2 more answers
Solve for in the diagram below.
ch4aika [34]
X is 35. 180=75+3x. 180-75/3=35
8 0
3 years ago
Need help with this question.
Vaselesa [24]

Answer:

4:1 (I think)

Step-by-step explanation:

Let's write some equations first:

For both prices increasing by 20:

\frac{x+20}{y+20} =\frac{5}{2}

then we can use cross multiplication

2x+40=5y+100

For both prices decreasing by 5:

\frac{x-5}{y-5} =\frac{5}{1}

same here:

5y-25=x-5

Using substitution for 5y, we get: 5y=x+20

2x+40=5y+100

2x+40=x+20+100

x=80

plugging this in to the second equation:

5y-25=x-5

5y-25=80-5

5y-25=75

5y=100

y=20

therefore we get x:y=80:20

4:1

4 0
2 years ago
Suppose the circumference of a circle is 4, pi. What is its diameter?
Vilka [71]
Your answer would be 4, because the equation for the circumference of a circle is π × diameter, so if you have 4 × π as the circumference, then 4 is the diameter.

I hope this helps!
3 0
3 years ago
Read 2 more answers
Help me I'm lost on this unit.​
Liula [17]

Answer:

remainder = 32

Step-by-step explanation:

Using synthetic division with divisor (x - 2) , that is h = 2

There is no x³ term so include zero as its coefficient in the table

2 | 3   0   - 3   2   - 8

    ↓    6   12   18    40

   ------------------------------

   3    6    9     20    32 ← remainder

   

   

6 0
3 years ago
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