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maxonik [38]
3 years ago
5

Given that g(x)=x^2​, find each of the following.

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
8 0
G(x) = x²
a) To find g(1) substitute with x = 1 at the function g(x)
∴ g(1) = 1² = 1

b) substitute with x = -2 at the function g(x)
∴ g(-2) = (-2)² = 4

c) substitute with x = -x at the function g(x)
∴ g(-x) = (-x)² = x²

d) substitute with x = 2y at the function g(x)
∴ g(2y) = (2y)² = 4y²

e) substitute with x = 2+h  at the function g(x)
∴ g(2+h) = (2+h)² = h² + 4h + 4





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F(x) = lnx/x
My name is Ann [436]
f(x) = \frac{lnx}{x}

(a) f'(x) = \frac{d}{dx}[\frac{lnx}{x}]
Using the quotient rule:
f'(x) = \frac{\frac{1}{x} \cdot x - lnx}{x^{2}}
f'(x) = \frac{1 - lnx}{x^{2}}

For maximum, f'(x) = 0;
\frac{1 - lnx}{x} = 0
lnx = 1, x = e

(b) <em>Deduce:
</em>e^{x} \geq x^{e}, x > 0
<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)
\frac{ln(e)}{e} \geq \frac{lnx}{x}
\frac{1}{e} \geq \frac{lnx}{x}, since ln(e) is simply equal to 1

Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.
\frac{x}{e} \geq lnx
x \geq elnx
x \geq ln(x^{e})

Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:
e^{x} \geq e^{ln(x^{e}})
e^{x} \geq x^{e}, as required.
3 0
3 years ago
PLEASE HELP ASAP!!! (Directions: Find the surface area of the prism) #5.
topjm [15]
SA= bh+2ls+lw
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SA=2740
5 0
3 years ago
46 2/3% of 28 please i need to know answer an work
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First, it would help to put 46 and 2/3 into an improper fraction: 140/3.

Then, since this is a percent, we put that improper fraction over 100: (140/3)/100 = 140/300.

Finally, we multiply this answer by 28 since "of" means multiply:

(140/300) * 28 = 196/15 = 13 1/15

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son4ous [18]
Add 0.1 to 0.0(54) to get 0.1(54).
5 0
3 years ago
Read 2 more answers
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